Exercise 10.6
The sound waves emitted by three sources A, B and C are represented in Fig. 10.31. If the frequency of A is maximum and C is minimum, identify the corresponding curves, and mark A, B and C on them.
Not cross-checked
NCERT prints no numerical answer for this exercise, so this working has not been cross-checked against the book.
NCERT’s answer
A - Green curve; B - Red curve; C - Blue curve
A is the green curve, B is the red curve and C is the blue curve.
All three waves travel in the same medium, so they share one speed \(\displaystyle v \), and \(\displaystyle v = \nu \times \lambda \) gives \(\displaystyle \lambda = \dfrac{v}{\nu} \) — the highest frequency must have the shortest wavelength.
A has the maximum frequency, so mark A on the curve whose crests are packed closest together — the green one.
C has the minimum frequency, so mark C on the curve with the widest crest-to-crest spacing — the blue one.
B is left with the in-between spacing, the red curve, giving \(\displaystyle \lambda_A < \lambda_B < \lambda_C \) while \(\displaystyle \nu_A > \nu_B > \nu_C \).
Write the letters A, B and C directly on their three curves in Fig. 10.31.