Mathematics · 2025
JEE Main · 28 January 2025, Shift 2 · Q4
If α+i β and γ+i δ are the roots of x^2-(3-2 i) x-(2 i-2)=0, i=√ -1, then α γ+β δ is equal to:
If $\displaystyle \alpha+i \beta$ and $\displaystyle \gamma+i \delta$ are the roots of $\displaystyle x^2-(3-2 i) x-(2 i-2)=0, i=\sqrt{-1}$, then $\displaystyle \alpha \gamma+\beta \delta$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle 2$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.