Mathematics · 2025
JEE Main · 29 January 2025, Shift 1 · Q2
Let |z_1-8-2 i| ≤ 1 and |z_2-2+6 i| ≤ 2, z_1, z_2 ∈ C. Then the minimum value of |z_1-z_2| is:
Let $\displaystyle \left|z_1-8-2 i\right| \leq 1$ and $\displaystyle \left|z_2-2+6 i\right| \leq 2, z_1, z_2 \in \mathrm{C}$. Then the minimum value of $\displaystyle \left|z_1-z_2\right|$ is :
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle 7$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.