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Mathematics · 2026

JEE Main · 21 January 2026, Shift 2 · Q2

Let z be the complex number satisfying |z-5| ≤ 3 and having maximum positive principal argument. Then 34|(5 z-12)/(5 i z+16)|^2 is equal to:

Let $\displaystyle z$ be the complex number satisfying $\displaystyle |z-5| \leq 3$ and having maximum positive principal argument. Then $\displaystyle 34\left|\frac{5 z-12}{5 \mathrm{i} z+16}\right|^2$ is equal to :
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.