Mathematics · 2026
JEE Main · 5 April 2026, Shift 2 · Q2
Let z_1, z_2 ∈ C be the distinct solutions of the equation z^2+4 z-(1+12 i)=0. Then |z_1|^2+|z_2|^2 is equal to:
Let $\displaystyle z_1, z_2 \in \mathbb{C}$ be the distinct solutions of the equation $\displaystyle z^2+4 z-(1+12 i)=0$. Then $\displaystyle \left|z_1\right|^2+\left|z_2\right|^2$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle 34$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.