Mathematics · 2026
JEE Main · 2 April 2026, Shift 1 · Q2
Let x and y be real numbers such that 50((2 x)/(1+3 i)-y/(1-2 i))=31+17 i, i=√ -1. Then the value of 10(x-3 y) is:
Let $\displaystyle x$ and $\displaystyle y$ be real numbers such that $\displaystyle 50\left(\frac{2 x}{1+3 i}-\frac{y}{1-2 i}\right)=31+17 i, i=\sqrt{-1}$. Then the value of $\displaystyle 10(x-3 y)$ is :
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle 75$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.