Mathematics · 2026
JEE Main · 4 April 2026, Shift 1 · Q3
Let z be a complex number such that | z +2|=| z -2| and ((z+3)/(z-i))=(π)/4. Then |z|^2 is equal to:
Let z be a complex number such that $\displaystyle |\mathrm{z}+2|=|\mathrm{z}-2|$ and $\displaystyle \arg \left(\frac{z+3}{z-i}\right)=\frac{\pi}{4}$. Then $\displaystyle |z|^2$ is equal to:
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle 9$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.