Mathematics · 2025
JEE Main · 4 April 2025, Shift 2 · Q3
Let the product of ω_1=(8+i) sin θ+(7+4 i) cos θ and ω_2=(1+8 i) sin θ+(4+7 i) cos θ be α+i β, i=√ -1. Let p and q be the maximum and the minimum…
Let the product of $\displaystyle \omega_1=(8+i) \sin \theta+(7+4 i) \cos \theta$ and $\displaystyle \omega_2=(1+8 i) \sin \theta+(4+7 i) \cos \theta$ be $\displaystyle \alpha+i \beta$, $\displaystyle i=\sqrt{-1}$. Let p and q be the maximum and the minimum values of $\displaystyle \alpha+\beta$ respectively. Then $\displaystyle \mathrm{p}+\mathrm{q}$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle 130$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.