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Mathematics · 2025

JEE Main · 28 January 2025, Shift 1 · Q3

Let O be the origin, the point A be z_1=√ 3 +2 √ 2 i, the point B (z_2) be such that √ 3 | z_2|=| z_1| and (z_2)= (z_1)+(π)/6. Then

Let O be the origin, the point A be $\displaystyle \mathrm{z}_1=\sqrt{3}+2 \sqrt{2} \mathrm{i}$, the point $\displaystyle \mathrm{B}\left(z_2\right)$ be such that $\displaystyle \sqrt{3}\left|\mathrm{z}_2\right|=\left|\mathrm{z}_1\right|$ and $\displaystyle \arg \left(z_2\right)=\arg \left(z_1\right)+\frac{\pi}{6}$. Then
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.