Exercise 6.1
Using a horizontal force F, a table is moved across the floor at a constant velocity. How much is the frictional force exerted by the floor on the table?
Not cross-checked
NCERT prints no numerical answer for this exercise, so this working has not been cross-checked against the book.
NCERT’s answer
F in the direction opposite to the applied force.
The frictional force is \(\displaystyle F \), acting in the direction opposite to the applied force.
The table moves at constant velocity, so its acceleration is zero.
By Newton's first law, zero acceleration means the net force on the table is zero.
Only two horizontal forces act — the applied force \(\displaystyle F \) forwards and friction backwards — so they must be balanced.
Hence force of friction \(\displaystyle = F \), directed backwards, opposite to the motion.
(The weight and the normal force are vertical and balance each other separately.)