Mathematics · 2022
JEE Main · 29 June 2022, Shift 2 · Q5
The value of lim_x → 1 ((x^2-1) sin^2(π x))/(x^4-2 x^3+2 x-1) is equal to:
The value of $\displaystyle \lim _{x \rightarrow 1} \frac{\left(x^2-1\right) \sin ^2(\pi x)}{x^4-2 x^3+2 x-1}$ is equal to:
Official answer
(4)
$\displaystyle \pi^2$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.