Mathematics · 2022
JEE Main · 30 June 2022, Shift 1 · Q23
Suppose lim_x → 0 (F (x))/x^3 exists and is equal to L, where F (x)= |a + sin x/2, - b cos x, 0; - b cos x, 0, a + sin x/2; 0, a + sin x/2, - b cos…
Suppose $\displaystyle \lim _{x \rightarrow 0} \frac{\mathrm{~F}(x)}{x^3}$ exists and is equal to L , where
$$\mathrm{F}(x)=\left|\begin{array}{ccc}
\mathrm{a}+\sin \frac{x}{2} & -\mathrm{b} \cos x & 0 \\
-\mathrm{b} \cos x & 0 & \mathrm{a}+\sin \frac{x}{2} \\
0 & \mathrm{a}+\sin \frac{x}{2} & -\mathrm{b} \cos x
\end{array}\right| .
$$
Then, -$\displaystyle 112$ L is equal to \_\_\_\_.
Official answer
14
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.