Mathematics · 2021
JEE Main · 26 February 2021, Shift 1 · Q67
The value of lim_h → 0 2{(√ 3 sin ((π)/6+h)- cos ((π)/6+h))/(√ 3 h(√ 3 cos h- sin h))} is:
The value of $\displaystyle \lim _{h \rightarrow 0} 2\left\{\frac{\sqrt{3} \sin \left(\dfrac{\pi}{6}+h\right)-\cos \left(\dfrac{\pi}{6}+h\right)}{\sqrt{3} h(\sqrt{3} \cos h-\sin h)}\right\}$ is :
Official answer
(2)
$\displaystyle \frac{4}{3}$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.