Mathematics · 2021
JEE Main · 31 August 2021, Shift 1 · Q67
lim_x → 0 (sin^2(π cos^4 x))/x^4 is equal to:
$\displaystyle \lim _{x \rightarrow 0} \frac{\sin ^2\left(\pi \cos ^4 x\right)}{x^4}$ is equal to :
Official answer
(3)
$\displaystyle 4 \pi^2$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.