Mathematics · 2025
JEE Main · 22 January 2025, Shift 2 · Q16
If lim_x → ∞((e/(1- e))(1/e-x/(1+x)))^x=α, then the value of (log_e α)/(1+ log_e α) equals:
If $\displaystyle \lim _{x \rightarrow \infty}\left(\left(\frac{\mathrm{e}}{1-\mathrm{e}}\right)\left(\frac{1}{\mathrm{e}}-\frac{x}{1+x}\right)\right)^x=\alpha$, then the value of $\displaystyle \frac{\log _{\mathrm{e}} \alpha}{1+\log _{\mathrm{e}} \alpha}$ equals :
Official answer
From NTA’s final answer key for this paper.
(4)
e
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.