Mathematics · 2022
JEE Main · 28 June 2022, Shift 2 · Q24
If lim_x → 1 (sin (3 x^2-4 x+1)-x^2+1)/(2 x^3-7 x^2+a x+b)=-2, then the value of (a-b) is equal to \ \ \ \.
If $\displaystyle \lim _{x \rightarrow 1} \frac{\sin \left(3 x^2-4 x+1\right)-x^2+1}{2 x^3-7 x^2+a x+b}=-2$, then the value of $\displaystyle (a-b)$ is equal to \_\_\_\_.
Official answer
11
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.