Mathematics · 2024
JEE Main · 6 April 2024, Shift 1 · Q17
The shortest distance between the lines (x-3)/2=(y+15)/-7=(z-9)/5 and (x+1)/2=(y-1)/1=(z-9)/-3 is
The shortest distance between the lines $\displaystyle \frac{x-3}{2}=\frac{y+15}{-7}=\frac{z-9}{5}$ and $\displaystyle \frac{x+1}{2}=\frac{y-1}{1}=\frac{z-9}{-3}$ is
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 4 \sqrt{3}$
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.