Mathematics · 2025
JEE Main · 24 January 2025, Shift 1 · Q14
Let in a ABC, the length of the side AC be 6, the vertex B be (1,2,3) and the vertices A, C lie on the line (x-6)/3=(y-7)/2=(z-7)/-2. Then the area…
Let in a $\displaystyle \triangle \mathrm{ABC}$, the length of the side AC be $\displaystyle 6$ , the vertex B be $\displaystyle (1,2,3)$ and the vertices $\displaystyle \mathrm{A}, \mathrm{C}$ lie on the line $\displaystyle \frac{x-6}{3}=\frac{y-7}{2}=\frac{z-7}{-2}$. Then the area (in sq. units) of $\displaystyle \triangle \mathrm{ABC}$ is:
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 21$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.