Mathematics · 2025
JEE Main · 4 April 2025, Shift 2 · Q14
Let the values of p, for which the shortest distance between the lines (x+1)/3=y/4=z/5 and r =( p i +2 j + k )+λ(2 i +3 j +4 k ) is 1/(√ 6), be a, b,…
Let the values of p , for which the shortest distance between the lines $\displaystyle \frac{x+1}{3}=\frac{y}{4}=\frac{z}{5}$ and $\displaystyle \overrightarrow{\mathrm{r}}=(\mathrm{p} \hat{i}+2 \hat{j}+\hat{k})+\lambda(2 \hat{i}+3 \hat{j}+4 \hat{k})$ is $\displaystyle \frac{1}{\sqrt{6}}$, be a, b, (a < b). Then the length of the latus rectum of the ellipse $\displaystyle \frac{x^2}{\mathrm{a}^2}+\frac{y^2}{\mathrm{~b}^2}=1$ is :
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle \frac{2}{3}$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.