Mathematics · 2025
JEE Main · 7 April 2025, Shift 1 · Q14
If the shortest distance between the lines (x-1)/2=(y-2)/3=(z-3)/4 and x/1=y/(α)=(z-5)/1 is 5/(√ 6), then the sum of all possible values of α is
If the shortest distance between the lines $\displaystyle \frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}$ and $\displaystyle \frac{x}{1}=\frac{y}{\alpha}=\frac{z-5}{1}$ is $\displaystyle \frac{5}{\sqrt{6}}$, then the sum of all possible values of $\displaystyle \alpha$ is
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle -3$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.