If the shortest distance between the lines (x-λ)/3=(y-2)/-1=(z-1)/1 and (x+2)/-3=(y+5)/2=(z-4)/4 is 44/(√ 30), then the largest possible value of |λ|…

If the shortest distance between the lines $\displaystyle \frac{x-\lambda}{3}=\frac{y-2}{-1}=\frac{z-1}{1}$ and $\displaystyle \frac{x+2}{-3}=\frac{y+5}{2}=\frac{z-4}{4}$ is $\displaystyle \frac{44}{\sqrt{30}}$, then the largest possible value of $\displaystyle |\lambda|$ is equal to $\displaystyle \_\_\_\_$.