Let the point (-1, α, β) lie on the line of the shortest distance between the lines (x+2)/-3=(y-2)/4=(z-5)/2 and (x+2)/-1=(y+6)/2=(z-1)/0. Then…

Let the point $\displaystyle (-1, \alpha, \beta)$ lie on the line of the shortest distance between the lines $\displaystyle \frac{x+2}{-3}=\frac{y-2}{4}=\frac{z-5}{2}$ and $\displaystyle \frac{x+2}{-1}=\frac{y+6}{2}=\frac{z-1}{0}$. Then $\displaystyle (\alpha-\beta)^2$ is equal to $\displaystyle \_\_\_\_$.