Mathematics · 2023
JEE Main · 6 April 2023, Shift 2 · Q1
Let the sets A and B denote the domain and range respectively of the function f(x)=1/(√(x -x)), where x denotes the smallest integer greater than or…
Let the sets A and B denote the domain and range respectively of the function $\displaystyle f(x)=\frac{1}{\sqrt{\lceil x\rceil-x}}$, where $\displaystyle \lceil x\rceil$ denotes the smallest integer greater than or equal to $\displaystyle x$. Then among the statements
(S1) : $\displaystyle A \cap B=(1, \infty)-\mathbb{N}$ and
(S2) : $\displaystyle A \cup B=(1, \infty)$
Official answer
From NTA’s final answer key for this paper.
(1)
only (S1) is true
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.