Let f: R -{0} → R be a function such that f ( x )-6 f (1/x)=35/(3 x)-5/2. If the lim_x → 0(1/(α x)+f(x))=β; α, β ∈ R, then α+2 β is equal to

Let $\displaystyle \mathrm{f}: \mathbb{R}-\{0\} \rightarrow \mathbb{R}$ be a function such that $\displaystyle \mathrm{f}(\mathrm{x})-6 \mathrm{f}\left(\frac{1}{\mathrm{x}}\right)=\frac{35}{3 \mathrm{x}}-\frac{5}{2}$. If the $\displaystyle \lim _{x \rightarrow 0}\left(\frac{1}{\alpha x}+f(x)\right)=\beta ; \alpha, \beta \in \mathbb{R}$, then $\displaystyle \alpha+2 \beta$ is equal to