Mathematics · 2025
JEE Main · 28 January 2025, Shift 2 · Q2
Let f:[0,3] → A be defined by f(x)=2 x^3-15 x^2+36 x+7 and g:[0, ∞) → B be defined by g (x)=(x^2025)/(x^2025+1). If both the functions are onto and S…
Let $\displaystyle f:[0,3] \rightarrow \mathrm{A}$ be defined by $\displaystyle f(x)=2 x^3-15 x^2+36 x+7$ and $\displaystyle \mathrm{g}:[0, \infty) \rightarrow \mathrm{B}$ be defined by $\displaystyle \mathrm{g}(x)=\frac{x^{2025}}{x^{2025}+1}$. If both the functions are onto and $\displaystyle \mathrm{S}=\{x \in \mathbf{Z}: x \in \mathrm{~A}$ or $\displaystyle x \in \mathrm{~B}\}$, then $\displaystyle \mathrm{n}(\mathrm{S})$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle 30$
More from Relations and Functions
- Let for some α ∈ R, f: R → R be a function satisfying f(x+y)=f(x)+2 y^2+y+α x y for all x, y ∈ R. If f(0)=-1 and f(1)=2, then the value of…2026
- Consider two sets A={x ∈ Z:|(|x-3|-3)| ≤ 1} and B={x ∈ R-{1,2}: ((x-2)(x-4))/(x-1) log_e(|x-2|)=0}. Then the number of onto functions f: A → B is…2026
- Let f: R-{0} → R be a function such that f(x)-6 f(1/x)=35/(3 x)-5/2. If the lim_x → 0(1/(α x)+f(x))=β; α, β ∈ R, then α+2 β is equal to2025
- If the domain of the function log_5(18 x-x^2-77) is (α, β) and the domain of the function log_(x-1)((2 x^2+3 x-2)/(x^2-3 x-4)) is (γ, δ), then…2025
- The function f:(-∞, ∞) →(-∞, 1), defined by f(x)=(2^x-2^-x)/(2^x+2^-x) is:2025
- The number of relations, defined on the set \{a, b, c, d\}, which are both reflexive and symmetric, is equal to:2026
- For the function f:[1, ∞) →[1, ∞) defined by f(x)=(x-1)^4+1, among the two statements: (I) The set S={x ∈[1, ∞): f(x)=f^-1(x)} contains exactly two…2026
- Let R={(x, y) ∈ N × N: log_e(x+y) ≤ 2}. Then the minimum number of elements, required to be added in R to make it a transitive relation, is ____.2026
JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.