Mathematics · 2025
JEE Main · 29 January 2025, Shift 1 · Q1
Define a relation R on the interval [0, (π)/2) by x R y if and only if sec^2 x- tan^2 y=1. Then R is:
Define a relation R on the interval $\displaystyle \left[0, \frac{\pi}{2}\right)$ by $\displaystyle x \mathrm{R} y$ if and only if $\displaystyle \sec ^2 x-\tan ^2 y=1$. Then R is :
Official answer
From NTA’s final answer key for this paper.
(1)
an equivalence relation
More from Relations and Functions
- Let for some α ∈ R, f: R → R be a function satisfying f(x+y)=f(x)+2 y^2+y+α x y for all x, y ∈ R. If f(0)=-1 and f(1)=2, then the value of…2026
- Consider two sets A={x ∈ Z:|(|x-3|-3)| ≤ 1} and B={x ∈ R-{1,2}: ((x-2)(x-4))/(x-1) log_e(|x-2|)=0}. Then the number of onto functions f: A → B is…2026
- Let f: R-{0} → R be a function such that f(x)-6 f(1/x)=35/(3 x)-5/2. If the lim_x → 0(1/(α x)+f(x))=β; α, β ∈ R, then α+2 β is equal to2025
- If the domain of the function log_5(18 x-x^2-77) is (α, β) and the domain of the function log_(x-1)((2 x^2+3 x-2)/(x^2-3 x-4)) is (γ, δ), then…2025
- The function f:(-∞, ∞) →(-∞, 1), defined by f(x)=(2^x-2^-x)/(2^x+2^-x) is:2025
- Let f:[0,3] → A be defined by f(x)=2 x^3-15 x^2+36 x+7 and g:[0, ∞) → B be defined by g(x)=(x^2025)/(x^2025+1). If both the functions are onto and…2025
- The number of relations, defined on the set \{a, b, c, d\}, which are both reflexive and symmetric, is equal to:2026
- For the function f:[1, ∞) →[1, ∞) defined by f(x)=(x-1)^4+1, among the two statements: (I) The set S={x ∈[1, ∞): f(x)=f^-1(x)} contains exactly two…2026
JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.