Mathematics · 2025
JEE Main · 29 January 2025, Shift 2 · Q2
Let S = N ∪{0}. Define a relation R from S to R by: R ={(x, y): log_e y=x log_e (2/5), x ∈ S, y ∈ R }. Then, the sum of all the elements in the range…
Let $\displaystyle \mathrm{S}=\mathbf{N} \cup\{0\}$. Define a relation R from S to $\displaystyle \mathbf{R}$ by :
$$\mathrm{R}=\left\{(x, y): \log _{\mathrm{e}} y=x \log _{\mathrm{e}}\left(\frac{2}{5}\right), x \in \mathrm{~S}, y \in \mathbf{R}\right\} .
$$
Then, the sum of all the elements in the range of R is equal to :
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle \frac{5}{3}$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.