Mathematics · 2025
JEE Main · 28 January 2025, Shift 2 · Q3
Let f: R -{0} →(-∞, 1) be a polynomial of degree 2, satisfying f(x) f(1/x)=f(x)+f(1/x). If f( K )=-2 K, then the sum of squares of all possible…
Let $\displaystyle f: \mathbf{R}-\{0\} \rightarrow(-\infty, 1)$ be a polynomial of degree $\displaystyle 2$ , satisfying $\displaystyle f(x) f\left(\frac{1}{x}\right)=f(x)+f\left(\frac{1}{x}\right)$. If $\displaystyle f(\mathrm{~K})=-2 \mathrm{~K}$, then the sum of squares of all possible values of K is :
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle 6$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.