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Mathematics · 2023

JEE Main · 6 April 2023, Shift 1 · Q21

Let A ={1,2,3,4, …., 10} and B ={0,1,2,3,4}. The number of elements in the relation R={(a, b) ∈ A × A: 2(a-b)^2+3(a-b) ∈ B} is ____

Let $\displaystyle \mathrm{A}=\{1,2,3,4, \ldots ., 10\}$ and $\displaystyle \mathrm{B}=\{0,1,2,3,4\}$. The number of elements in the relation $\displaystyle R=\left\{(a, b) \in A \times A: 2(a-b)^2+3(a-b) \in B\right\}$ is $\displaystyle \_\_\_\_$
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.