Mathematics · 2023
JEE Main · 6 April 2023, Shift 1 · Q10
Let 5 f(x)+4 f(1/x)=1/x+3, x>0. Then 18 ∫_1^2 f(x) d x is equal to:
Let $\displaystyle 5 f(x)+4 f\left(\frac{1}{x}\right)=\frac{1}{x}+3, x>0$. Then $\displaystyle 18 \int_1^2 f(x) d x$ is equal to:
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 10 \log _e 2-6$
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.