Let A={0,3,4,6,7,8,9,10} and R be the relation defined on A such that R={(x, y) ∈ A × A: x-y is odd positive integer or x-y=2}. The minimum number of…

Let $\displaystyle A=\{0,3,4,6,7,8,9,10\}$ and $\displaystyle R$ be the relation defined on $\displaystyle A$ such that $\displaystyle R=\{(x, y) \in A \times A: x-y$ is odd positive integer or $\displaystyle x-y=2\}$. The minimum number of elements that must be added to the relation $\displaystyle R$, so that it is a symmetric relation, is equal to $\displaystyle \_\_\_\_$.