Mathematics · 2022
JEE Main · 25 June 2022, Shift 2 · Q5
lim_x → (π)/2( tan^2 x((2 sin^2 x+3 sin x+4)^(1/2)-( sin^2 x+6 sin x+2)^(1/2))) is equal to
$\displaystyle \lim _{x \rightarrow \frac{\pi}{2}}\left(\tan ^2 x\left(\left(2 \sin ^2 x+3 \sin x+4\right)^{\frac{1}{2}}-\left(\sin ^2 x+6 \sin x+2\right)^{\frac{1}{2}}\right)\right)$ is equal to
Official answer
(1)
$\displaystyle \frac{1}{12}$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.