Mathematics · 2022
JEE Main · 25 June 2022, Shift 1 · Q9
Let f(x) be a polynomial function such that f(x)+f^′(x)+f^′ ′(x)=x^5+64. Then, the value of lim_x → 1 (f(x))/(x-1) is equal to:
Let $\displaystyle f(x)$ be a polynomial function such that $\displaystyle f(x)+f^{\prime}(x)+f^{\prime \prime}(x)=x^5+64$. Then, the value of $\displaystyle \lim _{x \rightarrow 1} \frac{f(x)}{x-1}$ is equal to :
Official answer
(1)
$\displaystyle -15$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.