Mathematics · 2022
JEE Main · 26 June 2022, Shift 1 · Q6
lim_x → 1/(√ 2) (sin ( cos^-1 x)-x)/(1- tan ( cos^-1 x)) is equal to:
$\displaystyle \lim _{x \rightarrow \frac{1}{\sqrt{2}}} \frac{\sin \left(\cos ^{-1} x\right)-x}{1-\tan \left(\cos ^{-1} x\right)}$ is equal to :
Official answer
(4)
$\displaystyle -\frac{1}{\sqrt{2}}$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.