Mathematics · 2020
JEE Main · 3 September 2020, Shift 1 · Q69
2 π-( sin^-1 4/5+ sin^-1 5/13+ sin^-1 16/65) is equal to:
$\displaystyle 2 \pi-\left(\sin ^{-1} \frac{4}{5}+\sin ^{-1} \frac{5}{13}+\sin ^{-1} \frac{16}{65}\right)$ is equal to :
Official answer
(2)
$\displaystyle \frac{3 \pi}{2}$
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.