Mathematics · 2020
JEE Main · 5 September 2020, Shift 1 · Q69
If S is the sum of the first 10 terms of the series tan^-1(1/3)+ tan^-1(1/7)+ tan^-1(1/13)+ tan^-1(1/21)+…., then tan (S) is equal to:
If $\displaystyle S$ is the sum of the first $\displaystyle 10$ terms of the series
$$\tan ^{-1}\left(\frac{1}{3}\right)+\tan ^{-1}\left(\frac{1}{7}\right)+\tan ^{-1}\left(\frac{1}{13}\right)+\tan ^{-1}\left(\frac{1}{21}\right)+\ldots .,
$$
then $\displaystyle \tan (S)$ is equal to :
Official answer
(1)
$\displaystyle \frac{5}{6}$
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.