Mathematics · 2022
JEE Main · 25 June 2022, Shift 2 · Q19
The value of tan^-1((cos ((15 π)/4)-1)/(sin ((π)/4))) is equal to:
The value of $\displaystyle \tan ^{-1}\left(\frac{\cos \left(\dfrac{15 \pi}{4}\right)-1}{\sin \left(\dfrac{\pi}{4}\right)}\right)$ is equal to :
Official answer
(2)
$\displaystyle -\frac{\pi}{8}$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.