Mathematics · 2025
JEE Main · 28 January 2025, Shift 2 · Q1
Let [x] denote the greatest integer less than or equal to x. Then the domain of f(x)= sec^-1(2[x]+1) is:
Let $\displaystyle [x]$ denote the greatest integer less than or equal to $\displaystyle x$. Then the domain of $\displaystyle f(x)=\sec ^{-1}(2[x]+1)$ is :
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle (-\infty, \infty)$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.