Mathematics · 2025
JEE Main · 28 January 2025, Shift 1 · Q13
cos ( sin^-1 3/5+ sin^-1 5/13+ sin^-1 33/65) is equal to:
$\displaystyle \cos \left(\sin ^{-1} \frac{3}{5}+\sin ^{-1} \frac{5}{13}+\sin ^{-1} \frac{33}{65}\right)$ is equal to:
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 0$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.