Mathematics · 2025
JEE Main · 4 April 2025, Shift 1 · Q13
Considering the principal values of the inverse trigonometric functions, sin^-1((√ 3)/2 x+1/2 √(1-x^2)),-1/2<x<1/(√ 2), is equal to
Considering the principal values of the inverse trigonometric functions, $\displaystyle \sin ^{-1}\left(\frac{\sqrt{3}}{2} x+\frac{1}{2} \sqrt{1-x^2}\right),-\frac{1}{2}<x<\frac{1}{\sqrt{2}}$, is equal to
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle \frac{\pi}{6}+\sin ^{-1} x$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.