Mathematics · 2022
JEE Main · 24 June 2022, Shift 2 · Q1
Let x * y=x^2+y^3 and (x * 1) * 1=x *(1 * 1). Then a value of 2 sin^-1((x^4+x^2-2)/(x^4+x^2+2)) is
Let $\displaystyle x * y=x^2+y^3$ and $\displaystyle (x * 1) * 1=x *(1 * 1)$. Then a value of $\displaystyle 2 \sin ^{-1}\left(\frac{x^4+x^2-2}{x^4+x^2+2}\right)$ is
Official answer
(2)
$\displaystyle \frac{\pi}{3}$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.