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Mathematics · 2020
JEE Main · 2 September 2020, Shift 1 · Q69
The domain of the function f(x)= sin^-1((|x|+5)/(x^2+1)) is (-∞,- a ] ∪[ a, ∞). Then a is equal to:
The domain of the function $\displaystyle f(x)=\sin ^{-1}\left(\frac{|x|+5}{x^2+1}\right)$ is $\displaystyle (-\infty,-\mathrm{a}] \cup[\mathrm{a}, \infty)$. Then a is equal to :
Official answer
(2)
$\displaystyle \frac{1+\sqrt{17}}{2}$
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.