Chemistry · 2019
JEE Main · 12 January 2019, Shift 1 · Q54
Two solids dissociate as follows A ( s ) ⇌ B ( g )+ C ( g ); K_p_1 =x atm^2; D ( s ) ⇌ C ( g )+ E ( g ); K_P_2 =y atm^2 The total pressure when both…
Two solids dissociate as follows
$$\begin{aligned}
& \mathrm{A}(\mathrm{~s}) \rightleftharpoons \mathrm{B}(\mathrm{~g})+\mathrm{C}(\mathrm{~g}) ; \mathrm{K}_{\mathrm{p}_1}=x \mathrm{~atm}^2 \\
& \mathrm{D}(\mathrm{~s}) \rightleftharpoons \mathrm{C}(\mathrm{~g})+\mathrm{E}(\mathrm{~g}) ; \mathrm{K}_{\mathrm{P}_2}=y \mathrm{~atm}^2
\end{aligned}
$$
The total pressure when both the solids dissociate simultaneously is :
Official answer
(3)
$\displaystyle 2(\sqrt{x+y}) \mathrm{atm}$
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JEE Main 2019 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.