Chemistry · 2022
JEE Main · 24 June 2022, Shift 1 · Q64
For a reaction at equilibrium A ( g ) ⇌ B ( g )+1/2 C ( g ) the relation between dissociation constant (K), degree of dissociation ( α ) and…
For a reaction at equilibrium
$$\mathrm{A}(\mathrm{~g}) \rightleftharpoons \mathrm{B}(\mathrm{~g})+\frac{1}{2} \mathrm{C}(\mathrm{~g})
$$
the relation between dissociation constant (K), degree of dissociation ( $\displaystyle \alpha$ ) and equilibrium pressure (p) is given by :
Official answer
(2)
$\displaystyle K=\frac{\alpha^{\frac{3}{2}} p^{\frac{1}{2}}}{(2+\alpha)^{\frac{1}{2}}(1-\alpha)}$
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JEE Main 2022 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.