Chemistry · 2022
JEE Main · 26 July 2022, Shift 1 · Q86
At 298 K, the equilibrium constant is 2 × 10^15 for the reaction: Cu ( s )+2 Ag^+( aq ) ⇌ Cu^2+( aq )+2 Ag ( s ) The equilibrium constant for the…
At $\displaystyle 298$ K, the equilibrium constant is $\displaystyle 2 \times 10^{15}$ for the reaction :
$$\mathrm{Cu}(\mathrm{~s})+2 \mathrm{Ag}^{+}(\mathrm{aq}) \rightleftharpoons \mathrm{Cu}^{2+}(\mathrm{aq})+2 \mathrm{Ag}(\mathrm{~s})
$$
The equilibrium constant for the reaction
$$\frac{1}{2} \mathrm{Cu}^{2+}(\mathrm{aq})+\mathrm{Ag}(\mathrm{~s}) \rightleftharpoons \frac{1}{2} \mathrm{Cu}(\mathrm{~s})+\mathrm{Ag}^{+}(\mathrm{aq})
$$
is $\displaystyle x \times 10^{-8}$. The value of $\displaystyle x$ is \_\_\_\_. (Nearest Integer)
Official answer
2
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JEE Main 2022 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.