SolveIt is under development
SolveItJEE Main
Question 52 / 72 · latest first
Chemistry · 2022

JEE Main · 25 June 2022, Shift 1 · Q86

The standard free energy change ( Δ G^° ) for 50% dissociation of N_2 O_4 into NO_2 at 27°C and 1 atm pressure is -x J mol^-1. The value of x is \ \…

The standard free energy change ( $\displaystyle \Delta \mathrm{G}^{\circ}$ ) for $\displaystyle 50$% dissociation of $\displaystyle \mathrm{N}_2 \mathrm{O}_4$ into $\displaystyle \mathrm{NO}_2$ at $\displaystyle 27$°C and $\displaystyle 1$ atm pressure is $\displaystyle -x \mathrm{~J} \mathrm{~mol}^{-1}$. The value of $\displaystyle x$ is \_\_\_\_. (Nearest Integer) [Given : $\displaystyle R=8.31 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}, \log 1.33=0.1239 \ln 10=2.3$ ]
ShareWhatsAppTelegram

More from Chemical Equilibrium

JEE Main 2022 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.