Chemistry · 2022
JEE Main · 25 June 2022, Shift 1 · Q86
The standard free energy change ( Δ G^° ) for 50% dissociation of N_2 O_4 into NO_2 at 27°C and 1 atm pressure is -x J mol^-1. The value of x is \ \…
The standard free energy change ( $\displaystyle \Delta \mathrm{G}^{\circ}$ ) for $\displaystyle 50$% dissociation of $\displaystyle \mathrm{N}_2 \mathrm{O}_4$ into $\displaystyle \mathrm{NO}_2$ at $\displaystyle 27$°C and $\displaystyle 1$ atm pressure is $\displaystyle -x \mathrm{~J} \mathrm{~mol}^{-1}$. The value of $\displaystyle x$ is \_\_\_\_. (Nearest Integer)
[Given : $\displaystyle R=8.31 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}, \log 1.33=0.1239 \ln 10=2.3$ ]
Official answer
710
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JEE Main 2022 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.