Chemistry · 2019
JEE Main · 8 April 2019, Shift 2 · Q57
For the following reactions, equilibrium constants are given: S ( s )+ O_2( g )⇌ SO_2( g ); K_1=10^52; 2 S ( s )+3 O_2( g )⇌ 2 SO_3( g ); K_2=10^129…
For the following reactions, equilibrium constants are given :
$$\begin{aligned}
& \mathrm{S}(\mathrm{~s})+\mathrm{O}_2(\mathrm{~g})\rightleftharpoons \mathrm{SO}_2(\mathrm{~g}) ; \mathrm{K}_1=10^{52} \\
& 2 \mathrm{~S}(\mathrm{~s})+3 \mathrm{O}_2(\mathrm{~g})\rightleftharpoons 2 \mathrm{SO}_3(\mathrm{~g}) ; \mathrm{K}_2=10^{129}
\end{aligned}
$$
The equilibrium constant for the reaction,
$$2 \mathrm{SO}_2(\mathrm{~g})+\mathrm{O}_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{SO}_3(\mathrm{~g}) \text { is }
$$
Official answer
(4)
$\displaystyle 10^{25}$
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JEE Main 2019 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.