Chemistry · 2019
JEE Main · 10 January 2019, Shift 1 · Q57
The values of K_p / K_c for the following reactions at 300 K are, respectively: (At 300 K, RT =24.62 dm^3 atm mol^-1 ) N_2( g )+ O_2( g ) ⇌ 2 NO ( g…
The values of $\displaystyle \mathrm{K}_{\mathrm{p}} / \mathrm{K}_{\mathrm{c}}$ for the following reactions at $\displaystyle 300$ K are, respectively :
(At $\displaystyle 300 \mathrm{~K}, \mathrm{RT}=24.62 \mathrm{dm}^3 \mathrm{~atm} \mathrm{~mol}^{-1}$ )
$$\begin{aligned}
& \mathrm{N}_2(\mathrm{~g})+\mathrm{O}_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NO}(\mathrm{~g}) \\
& \mathrm{N}_2 \mathrm{O}_4(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NO}_2(\mathrm{~g}) \\
& \mathrm{N}_2(\mathrm{~g})+3 \mathrm{H}_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NH}_3(\mathrm{~g})
\end{aligned}
$$
Official answer
(3)
$\displaystyle \begin{aligned}
& 1,24.62 \mathrm{dm}^3 \mathrm{~atm} \mathrm{~mol}^{-1}, \\
& 1.65 \times 10^{-3} \mathrm{dm}^{-6} \mathrm{~atm}^{-2} \mathrm{~mol}^2
\end{aligned}$
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JEE Main 2019 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.