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Chemistry · 2019
JEE Main · 9 January 2019, Shift 2 · Q57
Consider the following reversible chemical reactions: A_2( g )+ B_2( g ) K_1 ⇌ 2 AB ( g ) ….. (1); 6 AB ( g ) K_2 ⇌ 3 A_2( g )+3 B_2( g ) ….. (2) The…
Consider the following reversible chemical reactions :
$$\begin{align*}
& \mathrm{A}_2(\mathrm{~g})+\mathrm{B}_2(\mathrm{~g}) \stackrel{\mathrm{K}_1}{\rightleftharpoons} 2 \mathrm{AB}(\mathrm{~g}) \ldots . . \text { (1) }\\
& 6 \mathrm{AB}(\mathrm{~g}) \stackrel{\mathrm{K}_2}{\rightleftharpoons} 3 \mathrm{~A}_2(\mathrm{~g})+3 \mathrm{~B}_2(\mathrm{~g}) \ldots . . \text { (2) }
\end{align*}
$$
The relation between $\displaystyle \mathrm{K}_1$ and $\displaystyle \mathrm{K}_2$ is :
Official answer
(1)
$\displaystyle \mathrm{K}_2=\mathrm{K}_1^{-3}$
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JEE Main 2019 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.