Chemistry · 2021
JEE Main · 27 July 2021, Shift 2 · Q55
The equilibrium constant for the reaction A ( s ) ⇌ M ( s )+1/2 O_2( g ) is K_p =4. At equilibrium, the partial pressure of O_2 is \ \ \ \ atm.…
The equilibrium constant for the reaction
$$\mathrm{A}(\mathrm{~s}) \rightleftharpoons \mathrm{M}(\mathrm{~s})+\frac{1}{2} \mathrm{O}_2(\mathrm{~g})
$$
is $\displaystyle \mathrm{K}_{\mathrm{p}}=4$. At equilibrium, the partial pressure of $\displaystyle \mathrm{O}_2$ is \_\_\_\_ atm. (Round off to the Nearest Integer).
Official answer
16
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JEE Main 2021 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.